advance math mcq pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024
ibps rrb so officer sclae 2 3 single exam 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Lcm & Hcf
Ratio & Proportion
Percentage
Time & Work
Mensuration
Advance Math
Trigonometric Ratios & Identities
Average
Profit & Loss
A lady gives a dinner party to 5 guests to be selected from nine friends. The number of ways of forming the party of 5, given that two of the friends will not attend the party together is
Answer: (b)
Number of ways of selecting 5 guests from nine friends = $^9C_5$
Out of these, $^7C_3$ ways are those in which two of the friends occur together [3 more persons to be selected out of remaining 7]
∴ Number of ways, in which two of the friends will not attend the party together = $^9C_5 – ^7C_3$ = 91.
Five balls of different colours are to be placed in three different boxes such that any box contains at least one ball. What is the maximum number of different ways in which this can be done ?
Answer: (b)
These can be two cases :
Case I - One box contain 3 balls and rest two Contains 1 ball each.
Case II - One box contain 1 ball and rest two Contains 2 balls each.
Case 1 : Number of ways = $^5C_3 × ^2C_1 × ^1C_1$ = 20
Now, these 3 boxes can be arranged in ${3!}/{2!}$ among themselves, as two of them contains similar number of balls.
So, number of ways = 20 × ${3!}/{2!}$ = 60
Case II : Number of ways = $^5C_1 × ^4C_2 × ^2C_2$ = 30
Also, these 3 boxes can be arranged among themselves in ${3!}/{2!}$, as two of them contains similar number of balls.
Thus, number of ways = 30 × ${3!}/{2!}$ = 90
Now, either of case (I) or case (II) is possible,
Hence, total number of ways = 60 + 90 = 150
If the letters of the word 'PARKAR' are written down in all possible manner as they are in a dictionary, then the rank of the word 'PARKAR' is
Answer: (a)
Letters of the word PARKAR written in alphabetical
order are A A K P R R
Number of words starting with A is = 60
Number of words starting with K is = 30
Number of words starting with PAA is = 3
Number of words starting with PAK is = 3
Number of words starting with PARA is = 2
Number of words starting with PARKAR is = 1
∴ Rank of word PARKAR is 99
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions ?
Answer: (b)
X - X - X - X - X. The four digits 3, 3, 5,5 can be arranged
at (-) places in ${4!}/{2!2!}$ = 6 ways.
The five digits 2, 2, 8, 8, 8 can be arranged at (X) places in ${5!}/{2!3!}$ ways = 10 ways
Total no. of arrangements = 6 × 10 = 60 ways
A bag contains 15 tickets numbered 1 to 15. A ticket is drawn and replaced. Then one more ticket is drawn and replaced. The probability that first number drawn is even and second is odd is
Answer: (c)
In the first draw, we have 7 even tickets out of 15 and in the second we have 8 odd tickets out of 15.
Thus, (7/15) × (8/15) = 56/225.
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